(10x^2-13x+12)/(5x+1)

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Solution for (10x^2-13x+12)/(5x+1) equation: 


D( x )

5*x+1 = 0

5*x+1 = 0

5*x+1 = 0

5*x+1 = 0 // - 1

5*x = -1 // : 5

x = -1/5

x in (-oo:-1/5) U (-1/5:+oo)

(10*x^2-(13*x)+12)/(5*x+1) = 0

(10*x^2-13*x+12)/(5*x+1) = 0

10*x^2-13*x+12 = 0

10*x^2-13*x+12 = 0

DELTA = (-13)^2-(4*10*12)

DELTA = -311

DELTA < 0

1 = 0

1/(5*x+1) = 0

x belongs to the empty set

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